-0.03x^2-0.5x+60=0

Solution for -0.03x^2-0.5x+60=0 equation:

-0.03x^2-0.5x+60=0

a = -0.03; b = -0.5; c = +60;
Δ = b2-4ac
Δ = -0.52-4·(-0.03)·60
Δ = 7.45
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.5)-\sqrt{7.45}}{2*-0.03}=\frac{0.5-\sqrt{7.45}}{-0.06}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.5)+\sqrt{7.45}}{2*-0.03}=\frac{0.5+\sqrt{7.45}}{-0.06}
$